2w^2 + 8w +5 =0 none of these terms divide and I can't find a common factor
2007-10-31 11:41:29 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i think u have to use quadratic equation formula. u know that if ax^2 + bx + c = 0, then x = (-b±square root of (b^2 - 4ac)) divided by 2a
so the answer u get is (-4±root 6) divided by 2.
that's it, u can't do it using middle factorisation.
you're welcome:)
2007-10-31 11:52:57 · answer #1 · answered by Purbasha 2 · 1⤊ 0⤋
I once fell from first to third in a Southern California-wide math contest largely because I spaced out on a problem like that.
When a quadratic polynomial has no rational roots. Then it is "irreducible", and it's only factors are, in essence, 1 and itself.
2007-10-31 18:47:43 · answer #2 · answered by Curt Monash 7 · 0⤊ 1⤋
2w^2 + 8w +5 =0
w1 = ( -8 - sqrt(24))/4 = (-4 - sqrt(6))/2
w2 = (-4 + sqrt(6))/2
2007-10-31 18:45:01 · answer #3 · answered by Any day 6 · 1⤊ 0⤋
The equation does not have integer roots, but it still has real number roots. You can use the quadratic equation to find them (as the first answer shows).
2007-10-31 18:57:09 · answer #4 · answered by K N 123 3 · 0⤊ 0⤋