Assuming that the object is a regular polyhedron, the volume/surface area ratio should increase. If the surface area is kept constant, the volume would increase.
Think of a sphere as a polyhedron with an infinite number of edges. As you increase the number of edges, you will approach a sphere.
2007-10-31 11:35:01
·
answer #1
·
answered by gudspeling 7
·
0⤊
0⤋
Since you are interested in volume, I assume you have a three-dimensional object. Start by imagining a cube with unit length edges. It has 12 edges and 6 surfaces. Determine the surface area and volume of that cube. Now consider a many sided object. Do you see that it is approaching the shape of a sphere? See how the area/volume ratio of the sphere compares to a cube and you might have your answer.
2007-10-31 11:43:03
·
answer #2
·
answered by K N 123 3
·
0⤊
0⤋
Are you assuming you have the same area but a shape with more edges?
Ok then, the volume is the same because the V is Base Area times Height and even if you have more edges you will have the same base area
2007-10-31 11:28:34
·
answer #3
·
answered by landonastar 3
·
1⤊
0⤋
Assuming you're talking about regular polygons, and the widest part of the polygon stays the same measure, the shape gets rounder. A ball is the most compact shape, so the area decreases.
That's why a 9-inch square pan uses up more cake batter than a 9-inch round pan.
-------------
Okay, something's wrong with my explanation because it doesn't jive with eveybody else's. I'll get back to you.
------------
Aha, I can picture it now. Think of polygons inscribed in circle. The circle stays the same size. As the number of sides increases, the polygons do approach a circular shape, and they're still touching the circle, so the area expands.
2007-10-31 11:37:48
·
answer #4
·
answered by DWRead 7
·
0⤊
0⤋
Nothing, if the shape is a plane figure.
2007-10-31 11:27:36
·
answer #5
·
answered by ironduke8159 7
·
2⤊
0⤋
it increases
2007-10-31 11:33:34
·
answer #6
·
answered by H V 2
·
0⤊
0⤋