2log v3 (x) + 5 log v3 (y) - 4log v3 (z)
so thats 2 log sub 3 (x) + 5 log sub 3 (y) - 4 log sub3 (z)
I hope you get it.
2007-10-31 09:36:48 · 9 answers · asked by K Rose 3 in Science & Mathematics ➔ Mathematics
Remember that a log x = log x^a
So put all the numbers inside the logs:
log_3 (x²) + log_3 (y^5) + log_3( z^(-4) )
Now the next rule is:
log a + log b = log(ab)
log_3( x² y^5 z^(-4) )
You could also write this as:
log_3( x² y^5 / z^4 )
2007-10-31 09:41:38 · answer #1 · answered by Puzzling 7 · 2⤊ 0⤋
Let log be understood as log base 3 in the following:-
2 log x + 5 log y - 4 log z
log x² + log y^5 - log z^4
log (x² y^5 / z^4)
You don`t specify an actual question so this is as far as it goes ?
2007-10-31 11:52:47 · answer #2 · answered by Como 7 · 0⤊ 1⤋
Log base 3 of (x^2)(y^5) / z^4
2007-10-31 09:41:01 · answer #3 · answered by davidosterberg1 6 · 1⤊ 0⤋
LAWS:
n log a = log (a^n)
log a +log b = log ab
log a - log b = log (a/b)
so...
= log (x^3) + log (y^5) - log (z^4)
=log (x^3 * x^5) - log (z^4)
=log [(x^3 * x^5)/(z^4)]
the subs were all 3 so i didnt write'm.
good luck!!
2007-10-31 09:45:10 · answer #4 · answered by mahdi b 2 · 0⤊ 0⤋
I assume you have to simply the expression
= log base 3 (x^2y^5/z^4)
2007-10-31 09:41:07 · answer #5 · answered by norman 7 · 1⤊ 1⤋
2log v3 (x) + 5 log v3 (y) - 4log v3 (z)
= log v3 [(x^2)(y^5)/(z^5)]
2007-10-31 09:46:28 · answer #6 · answered by tj is cool 5 · 0⤊ 0⤋
I hated Logarithms in Highschool I wish you the best of luck I took a stab at it but i forget most of the rules. I think you will end up with 3 log sub....
2007-10-31 09:40:39 · answer #7 · answered by Anonymous · 1⤊ 4⤋
so using law of logs:
x^3(y^5)/z^4.
2007-10-31 09:43:58 · answer #8 · answered by tattoocandlehead 2 · 0⤊ 0⤋
thats correct
2007-10-31 09:40:23 · answer #9 · answered by Anonymous · 0⤊ 4⤋