What is sum of internal angles
angle(A) + angle(B) + angle(C)?
2007-10-31 09:18:35 · 4 answers · asked by Alexander 6 in Science & Mathematics ➔ Mathematics
Okay, let's see if I read this one right. I have a small equilateral triangle of side s, with interior angles A, and a larger equilateral triangle of side 2s, with interior angles B, such that the area of the larger triangle is 3 times that of the smaller. On a flat plane this is impossible, so maybe this is about spherical triangles. We know that, therefore, 3(3A-180) = (3B-180), and so we we have a system of 2 equations:
Cos(s) = Cos²(s) + Sin²(s)Cos(A)
Cos(2s) = Cos²(2s) + Sin²(2s)Cos(3A-(π/3))
Solving this system of equations gets you
3A = 210.19 degrees
2007-11-01 07:26:33 · answer #1 · answered by Scythian1950 7 · 1⤊ 1⤋
The sum of the angles in any triangle is 180, but if the two triangles are both equilateral with the ratio of their sides being 2:1, the ratio of their areas CANNOT be 3:1... it would have to be 4:1.
2007-10-31 09:27:54 · answer #2 · answered by chcandles 4 · 1⤊ 0⤋
Essentially, you're asking what are the sum of the internal angles of a triangle that does not exist. Well I say a non-existant triangle still has internal angles adding up to 180.
2007-10-31 14:04:36 · answer #3 · answered by Dr D 7 · 0⤊ 0⤋
180 degrees
2007-10-31 09:23:59 · answer #4 · answered by pinhead 4 · 1⤊ 0⤋