synthetic division and the factor theorem?

Question

determine if x+.5 is a factor of

P(x)=8x^4 - 36x^3 - 38^2 + 81x +45

Use a chart to show your work and then state whether or not x+,5 is a factor

Answer 1

8x^4 - 36x^3 - 38^2 + 81x +45

First, write the coefficients ONLY inside an upside-down division symbol; make sure you leave room underneath to write another row of numbers later:

|8 -36 -38 81 45
I______________

Put the test zero, x = -5, at the left:

   |8 -36 -38 81 45
-5 I______________

Carry down the first number, representing the leading coefficient:

   |8 -36 -38 81 45
-5 I______________
    8

Multiply this by the test zero, and carry the result up into the next column:
   |8 -36 -38 81 45
-5 I  -40
    I_____________
    8

Add down the column:
   |8 -36 -38 81 45
-5 I  -40
    I_____________
    8  -76

Multiply the previous result by the test zero, and carry the new result up into the last column:
   |8 -36 -38 81 45
-5 I  -40 380
    I_____________
    8  -76

Add down the column:
Multiply the previous result by the test zero, and carry the new result up into the last column:
   |8 -36 -38 81 45
-5 I  -40 380
    I_____________
    8  -76 342

Go on doing the same, till we get
Multiply the previous result by the test zero, and carry the new result up into the last column:
   |8 -36 -38   81   45
-5 I  -40 380 -1701 8145
    I_____________
    8  -76 342 -1629 8190

Answer 2

Question is unclear hence shortage of answers.
Divisor should be shown as (x + 0.5)
To show x + 0.5 is a factor, use synthetic division:-
- 0.5|8__-36__-38__81__45
___|____-4___20___9__-45
___|8__-40__-18__90___0

R = 0 thus x + 0.5 IS a factor.
P(x) = (x + 5)(8x³ - 40x² - 18x + 90)

Answer 3

How dare you.
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Well!