Adult tickets for the senior class play cost $5 each and the student tickets cost $3. A total of 1060 tickets costing $4500 were sold. How many student tickets were sold?
2007-10-31 06:25:37 · 9 answers · asked by wish on a star 1 in Science & Mathematics ➔ Mathematics
Let there be x adult tickets and y student tickets.
5x + 3y = 4500
x+y = 1060
Get one term on its own:
x+y = 1060
y = 1060-x
Substitute that into the other equation:
5x + 3(1060-x)=4500
5x + 3180 – 3x = 4500
2x + 3180 = 4500
2x = 1320
x = 660
Put the value of x in one equation
660 + y = 1060
y = 400
So there are 600 adult tickets and 400 student tickets.
2007-10-31 06:33:19 · answer #1 · answered by jlao04 3 · 0⤊ 0⤋
Number of student tix = s
Number of adult tix = a
Total cost of student tix = $3 * s = 3s
Total cost of adult tix = $5 * a = 5a
Eqaution 1:
3s + 5a = 4500
Equation 2:
s + a = 1060
So u gotta solve equations 1 and 2 simultaneously and u'll get "a" and "s". I dont have a calculator with me now but i hope this helps.
2007-10-31 06:31:51 · answer #2 · answered by Anonymous · 0⤊ 0⤋
3x + 5(1060-x)=4500
3x +5300-5x=4500
-2x+5300=4500
-2x=-800
x=400 student tickets
1060-400=660 adult tickets
2007-10-31 06:35:41 · answer #3 · answered by Ash 1 · 0⤊ 0⤋
let x be the number of adult
1060 - x would be the number of student
eq 5x +3(1060-x) = 4500
now you can solve for x= 660
2007-10-31 06:34:17 · answer #4 · answered by norman 7 · 0⤊ 0⤋
660 adult tickets
400 student tickets
2007-10-31 06:31:21 · answer #5 · answered by ERKAN B 2 · 0⤊ 0⤋
5(1060-x) + 3x = 4500
5300 - 2x = 4500
800 = 2x
x = 400
2007-10-31 06:35:50 · answer #6 · answered by Matt 3 · 0⤊ 0⤋
750
2007-10-31 06:30:11 · answer #7 · answered by Anonymous · 0⤊ 0⤋
i think it is about 40 or 50 s.tickets i dont remember
2007-10-31 06:33:43 · answer #8 · answered by Anonymous · 0⤊ 0⤋
you are correct it makes no sense because how many of each group entered.
2007-10-31 06:30:03 · answer #9 · answered by ? 7 · 0⤊ 0⤋