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2. 3x^2+10x+8
3. 5x^2+24x+27
4. 4x^2-12x+8
6. 9x^2+37x+4

2007-10-31 06:09:40 · 5 answers · asked by Diamond E 1 in Science & Mathematics Mathematics

5 answers

2. (3x+4)(x+2)
3. (5x+9)(x+3)
4. (4x-8)(x-1)
6. (9x+1)(x+4)

2007-10-31 06:16:09 · answer #1 · answered by norman 7 · 0 0

2. 3x^2+10x+8

Factors will look like (ax + b)(cx + d)

a & c must be 1 & 3

b & d can be 1 & 8 or 2 & 4

the factors must be

(3x + b)(x + d)

by trial and error, b = 4, d = 2

(3x + 4)(x + 2)

To factor these hard trinomials, see the lesson at the link below


3. 5x^2+24x+27

(5x + 9)(x + 3)


4. 4x^2-12x+8

4(x^2 - 3x + 2) {common factor}

4(x - 1)(x - 2)

6. 9x^2+37x+4

(9x + 1)(x + 4)

2007-10-31 06:23:31 · answer #2 · answered by kindricko 7 · 0 0

2. 3x^2+6x+4x+8=+ =3x(x+2)+4(x+2) = (x+2)(3x+4)
3. 5x^2+15x+9x+27 = 5x(x+3)+9(x+3) = (x+3)(5x+9)
4. 4(x^2-3x+2) = 4[x^2-3x+2] = 4[x^2-2x-x+2] = 4[x(x-2)-1(x-2)]
= 4(x-2)(x-1)
6. 9x^2+36x+x+4 = 9x(x+4)+1(x+4) = (x+4)(9x+1)

2007-10-31 06:35:51 · answer #3 · answered by rajesh v 2 · 0 0

Ans
2. (3x+4)(x+2)
3. (5x+9)(x+3)
4. (4x-8)(x-1)
6. (9x+1)(x+4)
SO where is the first & the 5th question

2007-10-31 06:19:51 · answer #4 · answered by Me C00L 2 · 0 0

2) (3x + 4)(x + 2)

3) (5x + 9)(x + 3)

4) (2x-4)(2x - 2) 0r 2(2x - 2)(x - 2)

6) (9x +1)( x + 4)

2007-10-31 06:23:44 · answer #5 · answered by Anonymous · 0 0

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