Organic chem help!! For 1 ethlycyclopentene, why are there 2 alkyl groups on C1 and 1 alkyl group on C2?

Question

I'm studying Markovnikov's rule and I know that the addition of HX to an alkene, the X goes on the C that has the most alkyl group, but i just see that C1 only contains the ethyl group, where is the other alkyl group?? and how does C2 even have 1 alkyl group??

Answer 1

C2 is the alkyl group. Consider the double bond >C=C<. the ring snakes around and binds to both ends. Thus the ring is an alkyl group on each C of >C=C<. The ethyl groyup is the second alkyl on C1. So adding HBr to the compound produces 1-bromo-1-ethylcyclopentane. The H+ goes on the less substituted C2.

Answer 2

its seems to me that the question is mixed up , or you probably were mixed up when reading the answer ,

Markovnikov's rule states that the hydrogen of the H-X
will end up on the carbon with the most hydrogens ( kinda like joining its friends) while the halide will join the carbon with the least hydrogens
and i wish i can draw the rxn here but i cant
so the double bond on the cyclopentene will break and the c1 holding the ethyl group will bond with the x while the c2 will bond with the H ...
thats what i think