help how do you solve these pairs?

Question

Give an ordered pair of numbers that satisfy the equation

4x+y=7

Answer 1

If we simplify in terms of one variable, it will be easier to examine this.

4x + y = 7 means that
y = 7 - 4x.

Now, we know that x is the independent variable. That means that we can pick any x, plug it into the equation and solve for y. So just pick an x. Here are some values you can use:

x = 0:
y = 7 - 4(0)
y = 7 - 0
y = 7
So your point is: (0,7)

x = 1:
y = 7 - 4(1)
y = 7 - 4
y = 3
So your point is: (1,3)

You can choose any x-value, plug it in and get a corresponding y-value.

Answer 2

Put in a value for x and solve for y (or vice versa)

So let x = 0 and solve for y to get 7. So the pair (0,7) satisfies the equation since

4(0) + y = 7

There are an infinite number of such pairs. Just let x = 1,2,3,4,5,.....

Answer 3

You pick one value, and then figure out the other.

For example, let x = 0

4(0) + y = 7
0 + y = 7
y = 7
So (0,7) is a pair

Try x = 1:
4(1) + y = 7
4 + y = 7
y = 7 - 4
y = 3
So (1,3) is another pair

Continue with x = 2:
4(2) + y = 7
8 + y = 7
y = 7 - 8
y = -1
So (2, -1) is another pair...

Got the idea?

Answer 4

First insert a value for "x". It can be any number you want. For example let's pick x=2

4x + y = 7
4x2 + y = 7
8+y = 7
y = -1

So the ordered pair is (2, -1)

Do this one more time with another value for "x"

There is no "wrong" number that you could use to set "x" equal to, your just trying to find what (x,y) values make the equation correct.

Answer 5

I'd pick any number you want for x and solve for y.

Let's start easy --> x = 0

4*0 + y = 7
y = 7
(0,7) is one pair

x = 1
4(1) + y = 7
y = 3
(1,3) is another pair

And you can keep doing this for a long time as there are a whole lotta pairs....

Answer 6

5X+Y=6

Answer 7

(1,3)