a scuba diver's tank contains 0.29 kg of O2 compressed into a volume of 2.3L
I know the answers..but i dont' know how to get it!!
(a) calculate the gas pressure inside the tank at 9 degrees C.
answer: 91 atm
(b) what volume would this oxygen occupy at 26 degrees C and .95 atm?
answer: 2.3 x 10^2 L
2007-10-31 02:54:25 · 3 answers · asked by WynnLasVegas 1 in Science & Mathematics ➔ Chemistry
n = (given mass) / (Molec Mass)
n = 290 g / 32g/mole
n = 9.06 moles of Oxygen gas
pV = nRT where: T is in Kelvin
p = { 9,06moles (0.082L atm/mole K) (9+273)K } / { 2.3L}
p = 91.1 atm
pV = nRT
(0.95 atm) V = (9.06 moles) (0.082 L atm /mole K) [(26 +273)K]
V = 233.8L = 2.3 x 10 ^ 2 L
2007-10-31 03:16:01 · answer #1 · answered by rene c 4 · 0⤊ 0⤋
To answer this, you need the gas equation 'PV = nRT'
Pressure times Volume = No of moles times 'R' constant times Temperature. You will need to look up the values of 'n' and 'R'
2007-10-31 02:59:12 · answer #2 · answered by Wayne G 3 · 0⤊ 0⤋
To get pressure it is:
Force divided by the area.
Figure it out~
2007-10-31 02:58:41 · answer #3 · answered by *Facepalm* 5 · 0⤊ 0⤋