line shown is (0,1), (-1,-4)
a) -1/5
b) 1/5
c) -5
d) 5
2007-10-31 02:31:30 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The slope of the line connecting the given two points is
m =(-4 - 1)/(-1 - 0) = 5
Thus the slope of the line perpendicular to the given line is the reciprocal of 5
m' = 1/5
2007-10-31 02:39:31 · answer #1 · answered by rene c 4 · 0⤊ 0⤋
For perpendicular lines the slope of the first line (m1) equals the negative recoprocal of the second line (m2), or stated as an equation m1 = -1 / m2.
m1 = delta y / delta x = (1-(-4) / (0-(-1) = 5/1 =5
m2 has to equal -1/5
2007-10-31 02:37:05 · answer #2 · answered by Jim M 3 · 0⤊ 0⤋
Okay firstly, the line's gradient is (1- (-4))/(0- (-1)) which is 5.
Therefore, the gradient of the perpendicular line is (-1)/5 which equals to -1/5, or a.
2007-10-31 02:46:25 · answer #3 · answered by kirlia7755 3 · 0⤊ 0⤋
a
2007-10-31 02:40:36 · answer #4 · answered by fiboway 2 · 0⤊ 0⤋