using the slope and Y intercept help?

Question

slope = - 4 and y-intercept = - 3

2)
slope= 1/2 and y intercept=0

Answer 1

If your problem is finding a equation of the line given the slope and the intercept, then here it is:

Using the slope-intercept form of the line:
y = mx + b
where,
m = slope and b= intercept

a) m = -4; b = -3
y = mx + b
y = -4x - 3

b) m = 1/2 ; b = 0
y = mx + b
y = 1/2x + 0
y = 1/2x

Answer 2

I'm not sure what you're asking here; the y-intercept is the point on the y-axis where the line crosses at x=0. The slope is the change in y as x increases. So if you had a slope of 2 and a y-intercept of 1, then the line would be at y=1 when x=0, and the y value would increase by 2 for every increase of 1 in the x value. At x=1, y=3 (1+2); at x=2, y=5 (3+2); and so on. The standard form of y=mx+b does the trick, with 'm' being the slope and 'b' being the intercept.

Answer 3

What are you trying to do put them in a formula??? If so then use y=mx+b. The m is the slope and the b is the y-intercept. So it would look like this y=-4x-3 for the 1st and y=1/2x+0 for the second. I dont know if thats what your trying to accomplish but hopefully it points you in the right direction.

Answer 4

I am guessing we are forming equations of lines.
lets use slope intercept form

y = mx + b where m=slope and b=y-intercept

1.) y = mx + b
y = -4x -3

2.) y = 1/2x + 0

Answer 5

Here is slope point form. Use it.


y = mx+b

Answer 6

do u have the midpoint