10 * 11 / 2 = 55
In general for the sum of 1 through n:
n (n + 1) / 2
So, now you tell me what is 1+2+3+ ... +98+99+100? No calculator allowed.
2007-10-29 20:19:13
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answer #1
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answered by Puzzling 7
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1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55
2007-11-01 16:05:46
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answer #2
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answered by Rayan Ghazi Ahmed 4
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1+2+3+4+5+6+7+8+9+10
number of terms (n)= 10
sum = n(n+1)/2 = 10(10+1)/2 = 110/2 = 55
2007-10-29 21:02:41
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answer #3
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answered by Anonymous
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a=1+2+3+4+5+6+7+8+9+10
a=10+9+8+7+6+5+4+3+2+1
2a=11+11+11+11+11+11+11+11+11+11
2a=10(11)
a= 5(11)
a=55
clear about this, this method is used by famous mathematician karl gauss, when his teacher ask him to count all numbers from 1 until 100, he solved in a short time, and at that time, he was only a child.
2007-10-30 01:10:18
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answer #4
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answered by datuk M 2
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1+2+3+4+5+6+7+8+9+10=55
another solution
there are ten numbers
the first number is 1
and the last number is 10
sum=n(a1+a10)/2=10(1+10)/2=5(11)=55
2007-10-29 20:23:27
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answer #5
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answered by ptolemy862000 4
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1+10=11
2+9=11
3+8=11
4+7=11
5+6=11
therefore if you sum the last and the first no. and then multiply the answer by n/2 (in this question:10/2=5) you'll find the answer.;)
1+10=11
10/2=5
11*5=55
good luck
2007-10-29 21:06:03
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answer #6
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answered by Anonymous
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55
2007-10-29 21:01:02
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answer #7
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answered by terrorblade 3
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55
2007-10-29 20:18:40
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answer #8
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answered by Aimee 3
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55
2007-10-29 20:18:36
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answer #9
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answered by Anonymous
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55 use a calculator next time
2007-10-29 20:19:10
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answer #10
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answered by Anonymous
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