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on the surface of Jupiter?

2007-10-29 19:32:29 · 3 answers · asked by Xquisite Shawtey 1 in Science & Mathematics Physics

3 answers

g = GM/R^2, where g = acceleration due to gravity at surface of planet (or where a space traveler positions himself if there is no hard surface), G = Newton's gravitational constant, M = mass of planet (or that part of it below the space traveler).

Taking ratios, G drops out,
gj/ge = (Mj / Me) / ( [Rj / Re ]^2) = (300) / ( [10]^2)

gj/ge = 300/100 = 3

Acceleration of gravity (and hence force of gravity) at nominal surface of Jupiter is 3 times that felt on earth.

2007-10-29 20:27:17 · answer #1 · answered by George S 3 · 0 0

Jupiter has no surface its a gas giant composed mainly of methane .

2007-10-30 02:40:33 · answer #2 · answered by Anonymous · 0 0

g = GM/R^2
g(J)/g(E) = (M(J)/M(E))(R(E)^2/R^J)^2)
g(J)/g(E) ≈ (300/1)(1/10^2) ≈ 3.0

2007-10-30 03:28:54 · answer #3 · answered by Helmut 7 · 0 0

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