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average velocity after t seconds of a falling object differs among celestial bodies.

earth -4.9t m/s
moon -.83t m/s
jupiter -11.44t m/s

suppose an object is dropped from 100 meter tall structures on the moon, earth and on jupiter write parametric representations of each motion

2007-10-29 18:08:38 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

100 meters is small compared to the radii of all three astronomical bodies so we can assume constant acceleration.

The formulas for constant acceleration are:

V(t) = V(0) + At
D(t) = V(0)t + (1/2)At^2

where:
V(t) is the velocity at time t
D(t) is the distance traveled at time t

The formula for V(t) is linear in t so the average velocity after t seconds is (V(0) + V(t))/2.

Since you have the formulas for average velocity, you can compute the acceleration A for each of the three and plug the results into the distance equation.

2007-10-31 16:59:29 · answer #1 · answered by simplicitus 7 · 0 0

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