Write 3/7-i as a complex number in standard form
2007-10-29 16:43:58 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
multiply top and bottom of fraction by conjugate of bottom:
3(7+i) / (7-i)(7+i) =
(21 + 3i) / (49 - i²) =
(21 + 3i) / 50 =
21/50 + (3/50)i
2007-10-29 16:51:15 · answer #1 · answered by Philo 7 · 0⤊ 0⤋
.0428571 - i
1,08797cis(-66.8 degrees)
I don't know what you mean by "standard form" but I assume the form above may be it. ( resembles polar coordinates, only the y-axis is now used for the imaginary numbers )
magnitude of vector ((3/7)i - (1)j)
= sqrt( (3/7)(3/7) + (1)(1) ) = 1.08797
angle = -90 + arctan( (3/7) / 1) = -66.8
answer = 1.08797 ( cos(-66.8) + isin(-66.8) )
answer = 1.08797 cis(-66.8) remember angles are in degrees
2007-10-29 23:58:16 · answer #2 · answered by revicamc 4 · 0⤊ 0⤋
is it 3 over (7-i)? because standard form is just like 4+i. i think. oh my gosh i don't even know.
2007-10-29 23:51:43 · answer #3 · answered by Anonymous · 0⤊ 0⤋