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Solve the equation ln(x + 5) - ln(3) = ln(x - 3).
a. 2.5
b. 5
c. 7
d. 4.5

2007-10-29 16:35:55 · 6 answers · asked by tessa 1 in Science & Mathematics Mathematics

6 answers

ln(x + 5) - ln(3) = ln(x - 3)

Division/subtraction rule of logs:
ln((x + 5) / 3) = ln(x - 3)

Subtract ln(x-3) from both sides:
ln((x + 5) / 3) - ln(x - 3) = 0

Division/subtraction rule of logs:
ln([(x + 5) / 3] / (x - 3)) = 0

Carry out fraction division:
ln((x + 5) / 3(x - 3)) = 0

Definition of ln:
e^0 = (x + 5) / 3(x - 3)

e^0 = 1:
1 = (x + 5) / 3(x - 3)

Cross multiply:
3(x - 3) = x + 5

Distribute:
3x - 9 = x + 5

Subtract x and add 9 to both sides:
2x = 14

Divide both sides by 2:
x = 7


Check answer:
ln(7 + 5) - ln(3) = ln(7 - 3)
ln(12) - ln(3) = ln(4)
ln(12/3) = ln(4)
ln(4) = ln(4)

2007-10-29 16:39:32 · answer #1 · answered by whitesox09 7 · 0 0

ln(x + 5) - ln(3) = ln(x - 3)
ln(x+5) - ln(x-3) = ln(3)
ln[(x+5)/(x-3)] = ln(3)

take the exponentials of both sides or make both sides as exponents of e. It will simplify to

(x+5)/(x-3) = 3
(x+5) = 3(x-3)
x + 5 = 3x - 9
x - 3x = -9 - 5
-2x = -14
x = 7

letter c is the answer...

2007-10-29 16:43:30 · answer #2 · answered by tootoot 3 · 0 0

ln(x+5) - ln(3) = ln(x-3)

ln((x+5)/3) = ln(x-3) [since log a - log b = log(a/b)

take out logs

(x+5)/3 = x-3

x+5 = 3x - 9

2x = 14

x = 7

2007-10-29 16:45:57 · answer #3 · answered by mohanrao d 7 · 0 0

ln(x+5) - ln(3) = ln(x-3)
ln[ (x+5)/3] = ln(x-3)
(x+5)/3 = x-3
x + 5 = 3x - 9
14 = 2x
x = 7, answer c.

2007-10-29 16:40:35 · answer #4 · answered by Philo 7 · 0 0

the answer is c. 7

2007-10-29 16:41:03 · answer #5 · answered by Roger M 2 · 0 0

(x+5)/3=(x-3)
x+5=3x-9
-2x=-14
x=7

c

2007-10-29 16:41:36 · answer #6 · answered by 3.14159 2 · 0 0

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