please help!!!!!!!!!?

0 ⤊

i was asked to find the 600th derivative of F(x)=xe^-x

2007-10-29 16:30:33 · 3 answers · asked by joech_02 1 in Science & Mathematics ➔ Mathematics

At the end of first derivative we have..
-xe^-x + e^-x

there fore at the end of 600th derivative
xe^-x + 600e^-x

2007-10-29 16:35:42 · answer #1 · answered by Adobe 3 · 0⤊ 0⤋

(x-600)exp(-x). Common case: (x-n)(-1)^n exp(-x), the formula can be proved by mathematical induction method.

2007-10-29 23:53:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋

d1 = e^-x - xe^-x = (1-x)e^-x
d2 = (x-2)e^-x
d3 = (3-x)e^-x

see how it goes? d600 must be (x-600)e^-x.

2007-10-29 23:37:42 · answer #3 · answered by Philo 7 · 0⤊ 0⤋