yes
3x (x^2 - 5x + 6)
3x (x+2) (x-3)
2007-10-29 15:54:15
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answer #1
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answered by Anonymous
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The quadratic formula gives you x= two somethings. The factors are then x-one something and x-the other something.
Back to RPM (russian peasant method). You factor out 3x, and remainng is x^2-5x+6. Even a Russian Peasant should figure out this is (x-2)(x-3).
2007-10-29 16:00:36
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answer #2
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answered by cattbarf 7
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Hello
Lets start with 3x^3 - 15x^2 + 18x.
Factor out the GCF: 3x(x^2 - 5x + 6)
This would be 3x(x-3)(x-2)
Hope this helps
2007-10-29 15:54:46
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answer #3
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answered by Jeff U 4
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Factor out 3x from the equation and you get 3x(x^2-5x+6) Then factor what in the parenthesis and you get 3x(x-2)(x-3)
2007-10-29 16:00:01
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answer #4
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answered by Tandra 2
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3x( x2 -5x + 6)
3x(x-3)(x-2)
If you can finagle, the roots by looking at the equation you can apply the quadratic formula to the x2 - 5x + 6
and get for the equation to equal zero x=3 or x=2
which means that (x-2) and (x-3) are factors of your original expression
2007-10-29 15:59:45
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answer #5
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answered by Grendel 2
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alright i can see that you can take out a 3X from this equation so your new equation would look like 3x(x^2-5x+6) then factor x squared minus five x plus s to be 3x(x-3)(x+2) there you go you can factor this problem
2007-10-29 17:03:06
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answer #6
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answered by ? 1
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You can't use the quadratic equation on a 3rd degree polynomial.
factor out 3x:
3x(x²-5x+6)
Use the quadratic equation on the (x2-5x+6) term
2007-10-29 15:56:15
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answer #7
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answered by DWRead 7
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First,factorise the 3x :
3x³ - 15x² + 18x=3x(x²-5x+6)
Do the further factorisation:
=3x(x-3)(x-2)
Final answer:3x(x-3)(x-2)
2007-10-29 16:08:05
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answer #8
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answered by Anonymous
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factor out the g.c.f. which is 3x
3x(x^2 - 5x + 6) now factor the trinomial
3x(x - 3)(x - 2)
can you see why the quad.form. gives 3 and 2
as answers?
2007-10-29 16:00:31
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answer #9
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answered by ssssh 5
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3x(x-2)(x-3)
2007-10-29 15:56:55
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answer #10
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answered by xandyone 5
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