Hi there,
I'm struggling with trying to find the zeros of the following;
x^4+25x^2+144
x^4-8x^3+17x^2-8x+16
Any help would be greatly appreciated. Thanks!
2007-10-29 15:49:21 · 2 answers · asked by Quasar 2 in Science & Mathematics ➔ Mathematics
Zeros do not have to be real numbers
2007-10-29 16:03:23 · update #1
The first eqution has no real zeroes, all are imaginary. Are you sure you have the equation right?
2007-10-29 15:59:47 · answer #1 · answered by Computer Guy 7 · 0⤊ 0⤋
Hello
x^4+25x^2+144
I went ahead and graphed this and found the solutions to be all imaginary since it doesn't cross the x axis.
So I used my equation solver in my TI-84+ and I got
x = 4i, -4i, 3i, -3i
I did the same with the next equation: x^4-8x^3+17x^2-8x+16.
I got x = 4+.00000152i, 4-.00000152i, 1i, -1i
Hope this helps
2007-10-29 23:02:20 · answer #2 · answered by Jeff U 4 · 0⤊ 0⤋