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For the reaction 2Al + 6HCI3 -> 2AlCI3 + 3H2 how many moles of H2 are produced by the complete reaction of 4.90 moles of Al?

2007-10-29 15:30:46 · 2 answers · asked by Lost 1 in Science & Mathematics Chemistry

2 answers

Try this:
2Al + 6HCl --> 2AlCl3 + 3H2
2 Al ~ 3H2
Mol H2 = 4.90 mol Al x 3H2/2Al = 4.90 x 1.5 =7.35 mol H2

2007-10-29 15:38:45 · answer #1 · answered by papastolte 6 · 0 0

You wouldn't have to pull out THAT much hair if you understood WHY you need these reactions. To answer your question, you only need to form a proportion:
4.9 moles Al/2 = x moles H2/3

2007-10-29 22:38:22 · answer #2 · answered by cattbarf 7 · 0 0

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