Joe bought 1/2 a case of cokes, and gave 1/6 of what he has to Sam.Mary bought 1/3 a case of cokes, and gave 1/4 of what she ahs to Sheila. How many more cokes did Sam have than Shelia?
2007-10-29 15:07:08 · 6 answers · asked by gizzydivenx3 1 in Science & Mathematics ➔ Mathematics
Presuming that there are 12 cokes in a case then.
Joe bought 1/2 case so he bought 6 and gave 1/6 away, which means he gave away 1 to Sam.
Mary bought 1/3 case, so she bought 4 and gave 1/4 away, so she also gave away 1 to Sheila
So Sam and Sheila both have a coke each.
So the answer is they have the same number.
2007-10-29 15:19:19 · answer #1 · answered by Petero 6 · 0⤊ 0⤋
say a case of cokes is 144 bottles.
(1/2) 144 = 72
Joe then gives (1/6), or 12, bottles to sam
Mary has (1/3), or 48, cokes and gave away 12 to sheila
sam and sheila both have the same amount of cokes
2007-10-29 15:14:55 · answer #2 · answered by Jason L 2 · 0⤊ 0⤋
You already got your answers. Next time, start with simple number like 12 or 24 in a case. Convert every statement in mathematical step for this specific number. Then proceed further. Once you have come to the conclusion, go back and generalize your steps. This way you will learn the logical steps for the next homework you receive.
2007-10-29 15:33:50 · answer #3 · answered by vcs7578 5 · 0⤊ 0⤋
How many cokes in a case??????
Assuming there are 12 cokes then they both end up with one coke a peice...so it is equal
2007-10-29 15:10:11 · answer #4 · answered by Anonymous · 0⤊ 0⤋
they both get a 1/12th of a thingy so they have the same amount so neither has more...
2007-10-29 15:15:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Maybe you shouldn't get people to do your homework for you!
2007-10-29 15:10:22 · answer #6 · answered by Laura B 1 · 0⤊ 1⤋