At an unknown distance from its base the top of a tower subtends an angle B which measures 45.799 degrees. From a distance along a line through the tower base and the first observation point and 893 feet further away the top of the tower subtends an angle A which measures 31.700 degrees. To within five feet the tower is ____ feet high
2007-10-29 14:45:59 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
552 is not the answer
2007-10-29 15:18:30 · update #1
Draw right angled triangle ABC right angled at C.
Horizontal CB = x ft
Extend CB to D
Horizontal BD = 893 ft
tan 45.8° = h/x
tan 31.7° = h / (x + 893)
x tan 45.8° = tan 31.7° (x + 893)
x (tan 45.8° - tan31.7°) = 893 tan 31.7°
x = 1378 ft ft
tan 45.8° = h / 1378
h = 1417 ft
Tower height is approx. 1420 ft
2007-11-04 01:16:00 · answer #1 · answered by Como 7 · 0⤊ 1⤋
h=x(tan45.799)
h=(x+893)(tan31.7)
x(tan45.799-tan31.7)=893(tan31.7)
x=552ft
I EVEN CHECKED WITH 7 OTHER PEOPLE THIS IS RIGHT
2007-10-29 14:54:08 · answer #2 · answered by Kunal Kerai 2 · 0⤊ 0⤋
wow i dont even now my math like jay-d
2007-10-29 14:54:04 · answer #3 · answered by LOKA_4_LIFE 1 · 0⤊ 0⤋
h=x(tan45.799)
h=(x+893)(tan31.7)
x(tan45.799-tan31.7)=893(tan31.7)
x=552ft
2007-10-29 14:52:03 · answer #4 · answered by Jay D 2 · 0⤊ 0⤋