simplify this please: 10x^2 - 30 x + 20 / x^2 - 1=?

Question

10x^2 - 30 x + 20 / x^2 - 1=

i'v tried it a million times but keep getting the wrong answers.

omg, thank you sooo much!!!!!!!!

Answer 1

[11]
10x^2-30x+20/x^2-1
=10(x^2-3x+2)/{(x)^2-(1)^2}
=10(x-1)(x-2)/(x+1)(x-1)
=10(x-2)/(x+1)

Answer 2

10x^2 - 30 x + 20 / x^2 - 1=
10(x^2 - 3 x + 2) / x^2 - 1=
10(x-2)(x-1) / ( x-1)(x+1) = thedenominator is a difference of 2 squares
now simplify
10(x-2)/(x+1)
and thats the answer!
or 10x-20/x+1

Answer 3

x=2 and x=1

First, multiply both sides by x^2 -1. This is pretty much cancelled out because that times 0=0
So now the problem is simplified to 10x^2 - 30 x + 20.
Divide everything by 10.
x^2 - 3 x + 2=0
Factor:
(x-2)(x-1)=0
x=2 and x=1

Answer 4

Ok, the nearest I could come to is:

10x^2-30x+20/x^2=1
Now multiply both sides of the equation with x^2 and you get:
10x^4-30x^3+20=x^2
Then you move numbers containing x to the left side:
10x^4-30x^3-x^2=-20
And now:
x^2(10x^2-30x-1)=-20
And this should be something you can work with. I don-t know what kind of problem you are solving (I know it's a polynomial, but I don't know for what purpose you need it), so this is the closest I could think of. Hope it helps!

Answer 5

Try factoring the numerator and the denominator

10(x^2 - 3x + 2) / (x+1)(x-1)

10(x-2)(x-1) / (x+1)(x-1)

Now cancel out the (x-1)

10(x-2) / (x+1)

Answer 6

Factor out 10 from the numerator to get
10 x (x^2 -3x + 2) / (x^2-1)
The numerator quadratic factors out and the denomintor quadratic is the sum and difference of squares. You will find that the same factor is in both the num and denom, and these cancel out. So you are left with 10 (x+a)/(x+b), where a and b are integer constants.

Answer 7

10(X^2-3X+20)/X^2-1
10(X-2)(X-1)/(X+1)(X-1)=CANCEL X-1
10(X-2)/(X+1)=10X^2-30X+20/X^2-1
:P

Answer 8

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