i know it ends up being something like
(x-2 ) (x +3 )
but the negatives are throwing me off and i dont know which factor goes in and if is positive or negative
2007-10-29 14:07:45 · 6 answers · asked by . 7 in Science & Mathematics ➔ Mathematics
Actually you have a positive and a negative factor so one must subtract from the other to get 5. You can't get to 5 the way you are doing it.
Try:
(x + 6)(x - 1)
2007-10-29 14:11:45 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
The 2 and 3 will never add to 5 if one must be negative to get -6. So use different factors, 6 &1. Then it must be
(x+6)(x-1)
2007-10-29 14:13:47 · answer #2 · answered by lizbth81 3 · 0⤊ 0⤋
X^2 + 5x - 6 = 0?
What two numbers do you ADD to get 5 and MULTIPLY to get -6?
ANS: 6 and -1
6 + (-1) = 5
6 * (-1) = -6
X^2 + 5x - 6 = 0
(x+6) (x-1) = 0
2007-10-29 14:19:19 · answer #3 · answered by Anonymous · 0⤊ 0⤋
My factors to this question are (x+6)(x-1)
So, the solution is x=-6 or 1
2007-10-30 23:03:28 · answer #4 · answered by someone else 7 · 0⤊ 0⤋
x^2 + 5x - 6 = 0
(x - 1)(x + 6)
x = 1
x = -6
2007-10-29 14:46:05 · answer #5 · answered by Eduardo (lalo) Leal 2 · 0⤊ 0⤋
x^2 + 5x - 6 = 0
(x-1)(x+6) = 0
CHECK:
(x-1)(x+6) = x(x+6) - (x+6) = x^2 + 6x - x - 6 = x^2 + 5x - 6
2007-10-29 14:11:42 · answer #6 · answered by PeterT 5 · 1⤊ 0⤋