English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

5a^2=26a+24

Do you get the answer 6/5 and 4?

2007-10-29 12:40:15 · 5 answers · asked by Wonderer 1 in Science & Mathematics Mathematics

5 answers

i got -8 and 6

2007-10-29 12:44:36 · answer #1 · answered by Curious Georgette 1 · 0 0

6/5 and 4 are the solutions of

5a^2 = 26a - 24

that is, of 5a^2 - 26a + 24 = 0. Your problem, as typed, is
5a^2 - 26a - 24 = 0

Did you mistype the problem? If not, the answers are 6 and -4/5.

2007-10-29 12:52:35 · answer #2 · answered by Ron W 7 · 0 0

I didn't get that answer. One thing you can do to check is literally subbing those values into the equation (in place of a) and checking if you got 0.

Here is what I did to solve it:
Move everything to one side:
5a^2-26a-24

Now here is the tricky part. You have to find the two values of x. I usually compose a table. On the first side I put the factors of 5, and on the second I put the factors of -24.

So my table looks like:
5a | 4
1a | -6

To check if your answer is correct cross multiply the two numbers and see if the add up to the middle term in your eq'n (-26).
So
5(-6)+4(1)
=-30 +4
=-26

Therefore the equation would be (5a-4)(a-6)

Hope this helps!

2007-10-29 12:51:20 · answer #3 · answered by Mayx 3 · 0 0

You can always check by plugging in the values and see of the equation holds true. However, here's my factoring:

5a^2 - 26a + 24 = 0

(5a - 6 )(a - 4) = 0

a = 6/5 or a = 4

You're good!

2007-10-29 12:44:37 · answer #4 · answered by Marley K 7 · 0 0

5a^2-26a-24=0

Using the quadratic equation I end up with 6 and -0.8

You can check them yourself by plugging the results you get back into the original question and seeing if it results in a true statement.


WHEN IN DOUBT ABOUT FACTORING USE THE QUADRATIC EQUATION! WRONG ANSWERS ARE BEING GIVEN IN HERE!!!

2007-10-29 12:48:42 · answer #5 · answered by Milo 3 · 0 0

fedest.com, questions and answers