equations?

Question

How do you do a problem that says write an equation of the line that passes through point P and is parallel to the line with the given equation.

P(-3,6), y= -x - 5.

Answer 1

if they are parallel they have the same slope
y= -x - 5
slope is -1
so if the point has the coordinates (-3,6) you just substitute in the general line equation
y - y1 = m(x - x1)
y - 6 = -1(x -(-3))
y - 6 = -x -3
y = -x + 3, and this is the equation of the line you're looking

Answer 2

Given line has m = - 1
Parallel line has m = - 1 and passes thro`(-3,6)
y - 6 = (-1) (x + 3)
y = - x - 3 + 6
y = - x + 3

Answer 3

parallel lines have the same slope.
So the line you want has the equation

y = -x + b
Now plug in -3 for x and 6 for y to solve for b.
6 = 3 + b
b=3

y = -x + 3

Answer 4

you use y=mx+c

to be parallel the m must be the same

set x =0 and y=c (gives the intercept on the y axis)
set y=0 and c= -mx

y1=m1 x1+c1
y2=m2 x2+c2

you can add or subtract these
or divide them

and you can enter -3 , 6 into them

y=mx +c we know that m=-1
you have values for x and y
.....

Answer 5

the slope would be -1
then you have to do
y-y1=M(x-x1)
y-6=-1(x+3)
y=-1x+3 is the answer