find 4 consecutive odd integers such that the sum of the second and fourth is 132.?

Answer 1

im not telling you yr homework answers. do it yrself.

Answer 2

Hi,

This cannot be done.

Any odd number can be expressed as (2x+1) where x is any integer. So the four consecutive odd numbers would be (2x+1), (2x+3), (2x+5), (2x+7).

The sum of the second and fourth is supposed to be 132.

(2x+3) + (2x+7) = 132

4x + 10 = 132; 4x = 122; x = 30.5

2x = 61 so the numbers in the series are 62, 64, 66, 68. The sum of 64 + 68 = 132.

Did you mean consecutive even numbers?

Answer 3

let x be the second odd integer, then the forth one would be x+ 4

x +(x+4) = 132
2x + 4 = 132 SUBTRACT 4 from both sides
2x = 128 DIVIDE both sides by 2
x = 128/2 or 64 which is an even number
The even numbers would be 62, 64, 66, and 68 where the sum of 64 and 68 is 132

I tried the odd numbers near that, 61 63 65 67 or 69, but none totaled to 132

65 + 69 = 134 and 63 + 67 = 130

Answer 4

There is no correct answer for this question. You can get 132 using four consecutive odd numbers, but not by adding the 2nd and 4th.

You can get 132 with 63, 65, 67, 69 adding the 1st and 4th, or the 2nd and 3rd. Using 61, 63, 65, 67, you get 132 by adding the 3d and 4th. Using 65, 67, 69, 71, by adding the 1st and 2nd. It's impossible as you have stated the question.

Answer 5

odd integers are spaced two apart
x = 1st odd
x + 2 = 2nd odd
x + 4 = 3rd odd
x + 6 = 4th odd

Second + fourth = 132
x + 2 + x + 6 = 132
2x + 8 = 132
2x = 124
x = 62 this isn't odd so you must have either typed something wrong or there is no solution.

For example, if you had said the sum was 134
then the equation would have gotten to the point of
2x + 8 = 134
2x = 126
x = 63

Numbers would have been 63, 65, 67, 69

Answer 6

Let the integers be n, n+2, n+4 and n+6 respectively.

You know that the 2nd (n+2) and the 4th (n+6) will add to be 132.

n+2 + n+6 = 132
2n + 8 = 132
2n = 124
n = 62

But that would make them consecutive *even* integers 62, 64, 66 and 68.

Are you sure you stated this correctly?

Answer 7

4 consecutive odd integers would be ie 1 3 5 7 - since i don't exactly need the first or third, i'll call the second one x, and the fourth one would be x+4

so x + x + 4 (sum of first and fourth) needs to be 132.
x + x + 4 = 132.

solve this and you have your second odd integer. now you just need one before it, and two after it

Answer 8

132 is not an odd integer.

Answer 9

61, 63, 65, 67...
the last two intergers added together equal 132... but there are multiple answers.

Answer 10

Let's call them (2k-3), (2k-1), (2k+1) and (2k+3):
(2k-1)+(2k+3) = 132, 4k+2=132, 4k=130, k=32.5. So the first would be 2(32.5)-3 = 62. So it can't happen.