if Sin A= 8/10 and A lies between 360 and 0., determine Tan A.?

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if Sin A= 8/10 and A lies between 360 and 0., determine Tan A.?

2007-10-29 10:58:04 · 3 answers · asked by yeshila 1 in Science & Mathematics ➔ Mathematics

3 answers

sin A = 4 / 5
A = 53.1° , A = 126.9°
tan 53.1° = 1.33
tan 126.9° = -1.33

2007-11-02 08:17:04 · answer #1 · answered by Como 7 · 1⤊ 0⤋

Since sin A > 0, it can only be in quadrant I and II
In quadrant I
Tan A = 8/6 = 4/3

In quadrant II
Tan A = -4/3
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Ideas: Use the 6-8-10 quadratic triple.

2007-10-29 18:09:32 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋

sin = opp / hyp.
if opp = 8 and hyp = 10 then ajdecent side = 6

tan = opp / adj = 8/6 = 4/3

2007-10-29 18:09:13 · answer #3 · answered by davidosterberg1 6 · 0⤊ 0⤋