To move a large crate across a rough floor, you push on it with a force F at an angle of 21°, below the horizontal. Find the acceleration of the crate, given that the mass of the crate is m = 30 kg, the applied force is 325 N and the coefficient of kinetic friction between the crate and the floor is 0.46.
Thanks a lot again.
2007-10-29 10:40:17 · 1 answers · asked by acousticplaya90 1 in Science & Mathematics ➔ Physics
Start by drawing a free body diagram. The forces acting on the crate are its own weight, the applied force, a normal force, and a friction force. Don't forget that the applied force has a horizontal component and a vertical component. Do a force balance in the vertical direction to find the normal force the floor exerts on the crate. Use that to calculate the friction force, Ff = uN, where u is the coefficient of friction and N is the normal force. Then add the friction force and the horizontal component of the the applied force, which act in opposite directions (so the magnitudes are subtracted), to find the net horizontal force on the crate. Using F = ma, find the acceleration of the crate.
2007-11-01 03:33:28 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋