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A house painter is standing on a uniform, horizontal platform that is held in equilibrium by two cables attached to supports on the roof. The painter has a mass of 77 kg and the mass ofthe platform is 19.6 kg. The distance from the left end of the platform to where the painter is standing is d = 2.0 m and the total length of the platform is 4.9 m.
a) How large is the force exerted by the left-hand cable on the platform?
b) How large is the force exerted by the right-hand cable?

A uniform diving board, of length 5.0 m and mass 55 kg, is supported at two points; one support is located 3.4 m from the end of the board and the second is at 4.6 m from the end (see the figure below). What are the forces acting on the board due to the two supports when a diver of mass 63 kg stands at the end of the board over the water? Assume that these forces are vertical. [Hint: In this problem, consider using two different torque equations about different rotation axes.
Left support ____
Right support

2007-10-29 10:20:19 · 1 answers · asked by Pr0ject 1 in Science & Mathematics Physics

1 answers

Using torque =0 summed about the right hand cable
TR*4.9-77*g*2.9-19.6*g*2.45=0
solve for TR

TR=542.64 N

The right is
9.8*(77+19.6)-542.64
=404.04 N

For the diving board

summing about the left support
F2*1.2-55*2.1*9.81-63*9.81*4.6=0
F2=3313 N upward
this is the right support

summing about the right support

63*9.81*3.4+0.9*9.81*55-1.2*F1=0
F1=2155 N downward
check
the weights are
63*9.81+9.81*55
=1158
and
3313-2155=1158

j

2007-10-31 03:06:21 · answer #1 · answered by odu83 7 · 0 0

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