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Question

A 520. g piece of copper tubing is heated to 91.7°C and placed in an insulated vessel containing 57.0 g of water at 37.0°C. Assuming no loss of water and heat capacity for the vessel of 10.0 J/K, what is the final temperature of the system (c of copper = 0.387 J/g·K)?

Answer 1

Use LAGEBRA!
Specific heat of Water: 4.18J/g·°C
Let the final temperature of the system be T°C.
(520g)*(0.387 J/g·°C)*(91.7°C - T°C) = (10.0 J/°C + 57.0g* 4.18J/g·°C)*(T°C - 37.0°C)
Cancel all the units, we have:
520*0.387*(91.7 - T) = (10.0 + 57.0* 4.18)*(T - 37.0)
Now you do the math to get T.