English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2 answers

It takes one calorie to raise the temperature of 1 gram of water by 1 deg C.

It would require 30,000 calories to raise 1000g of water by 30 deg C.

The conversion of calories to joules is: 1 cal = 4.184 J

Therefore: 30,000 cal x 4.184 = approx. 126 kJ

2007-10-29 09:45:39 · answer #1 · answered by THC123 1 · 0 0

Delta T = 50-20 = 30°C

q = m c (delta T)

q = 1000.0 g (4.184 J/mol°C) (30°C)
q = 125520 J = 125 kJ

2007-10-29 16:45:03 · answer #2 · answered by hcbiochem 7 · 0 0

fedest.com, questions and answers