For this problem, we are asked to find the points on the curve where the tangent is horizontal or vertical.
1. x = Cos(3t), y = 2sin(t)
I know that dy/dt = 2Cos(t) and
dx/dt = -3sin(3t)
And that you set dy/dt equal to 0 to find the horizontal tangents, and dx/dt equal to 0 to find the vertical tangents. However, I am wondering what are the correct restrictions to apply in each case (for dx/dt and dy/dt) to find the correct number of the respective horizontal and vertical tangents. For instance, since dy/dt involves cosine, would I restrict it to values between 0 and pi (including these endpoints as well) and thus end up with a result that the horizontal tangent only occurs at pi/2, since this is the only location within the interval between 0 and pi where the cosine is 0?
Similarly, for dx/dt, since it involves sine, would I restrict it to 0 to pi/2 (including these endpoints as well) and thus say that the vertical tangents occurs at 0 and pi/3 (pi/3 because of the 3 in the expression, which cancels out with the 3 in pi/3 making it just pi, where sine is 0) because these are the only points in the given expression where the sine is 0 for the interval of 0 to pi/2?
Is all of this correct? If not, please indicate what are the correct restrictions to apply in each case (dx/dt and dy/dt), and why they are not what I listed above.
2007-10-29
08:32:10
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1 answers
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asked by
Vortex
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Science & Mathematics
➔ Mathematics