Can you help me with these two chemical equations?

Question

I had to carry out these experiments:
Mix calcium carbonate with dilute hydrochloric acid in a test tube with a side arm and dip the delivery in a test tube containing calcium hydroxide and cork the test tube to trap any gases. A gas was formed and a white precipitate formed with the CaOH. my first equation was:
CaCo3+2HCl--> CaCl2+H2O+Co2.... I need another equation .. something to do with the Co2 forming something.....

The next experiment was to mix potassium manganate (VII) with a few cm^3 of concentrated hydrochloric acid.....and a gas was given off.. something like chlorine.... what would be the equations?

and can you tell me how these gases were formed?

Answer 1

CaCO3(s) + 2HCl(aq) --> CaCl2(aq) + H2O + CO2(g)
CO2(g) + Ca(OH)2(aq) --> CaCO3(s) + H2O
Please do not write CO2 as Co2, Ca(OH)2 as CaOH.

You mean potassium permanganate KMnO4 to react with HCl. This is a redox reaction, where MnO4- reduces to Mn(2+), and 2Cl- oxydizes to Cl2(g).
The equation can be derived from:
MnO4- + 8H+ + 5e(-) ==> Mn(2+) + 4H2O...(1)
2Cl- = Cl2 + 2e(-)...(2)
2(1) + 5(2):
2MnO4- + 16H+ + 10Cl- ==> 2Mn(2+) + 8H2O + 5Cl2
Or:
2KMnO4 + 16HCl ==> 2MnCl2 + 2KCl + 8H2O + 5Cl2