Steady Flow Energy?

Question

A water turbine operates from a water supply that is 100 ft above the turbine inlet. It discharges to the atmosphere through a 6-in. diameter pipe with a velocity of 25 ft/s. If the reservoir is infinite in size, determine the power out of the turbine if the density of water is 62.4 lbm/ft3.

Answer 1

Note lbm are converted to slug by dividing by g to allow correct conversions among force, velocity, pressure, power.
Volume flow rate Vdot = V*area = 25 * pi*0.25^2 ft^3/s
density = 62.4/g slug/ft^3
pressure = density*g*height = 62.4*height lbf/ft^2
Power in = Vdot*pressure ft-lbf/s
Mass flow rate mdot = Vdot*density slug/s
Power out = mdot*V^2/2 ft-lbf/s
Assuming a 100% efficient turbine,
Turbine output power = power in - power out

Answer 2

energy equation (I think): delta h + delta v^2/2g + delta p* gamma = constant

or

h1 + v1^2/2g + p1gamma = h2 + v2^2/2g + p2gamma + Wturbine dot.
( units in length, weird, I know)
h1 = 100 ft
h2 = 0 ft

v1 = 0 m/s
v2 = 25 ft/s
p1 = p2 = atm.

solve for Wturbine

but then I forgot what to do with it.