2^2y=4.....?

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2^2y=4

2007-10-29 06:18:51 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2^(2y)=4
2^(2y) = 2^2
Since bases are e, exponents are =, so
2y = 2
y=1
No logarithms needed.

2007-10-29 06:24:35 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋

2^2y = 2^2

so y=1

2007-10-29 13:24:45 · answer #2 · answered by well wisher 2 · 0⤊ 0⤋

Take the log of both sides, then you can move the "2y" to the front, and solve for y.

2007-10-29 13:21:26 · answer #3 · answered by Dave 6 · 0⤊ 0⤋