is this right?

0 ⤊

(40y^-2q) divided by (2y^4 q^9)

=38y^-6 q^-8

2007-10-29 05:23:33 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

(40y^-2 q) / (2y^4 q^9) =

40/2 y^-2/y^4 q/q^9 =
20 y^-6 q^-8

2007-10-29 05:28:08 · answer #1 · answered by PeterT 5 · 0⤊ 0⤋

No
Should be 20y^-6q^-8 or preferably 20/(y^6q^8).
It is usually preferred to have final answer with all positive
exponents.

2007-10-29 12:28:57 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋