what is 16/y + 3y/4=?

Question

this is a algebra question

Answer 1

[03]
16/y + 3y/4
The GCF of y and 4 is 4y
Given expression
=(64+3y^2)/4y

Answer 2

First you must have a common denominator.
the common denominator would be 4y.

so
16/y becomes 4*16/4y

and
3y/4 becomes 3y^2/4y

Now this becomes

(64+3y^2)/4y

my best guess

Answer 3

You can't solve that because its not an equation. If you don't know what y is then you can't do anything --> you have 2 unknowns. All you can do is write it as 64+3y^2

Answer 4

Assuming that both the question mark and the variable y here represent an integral value and the that we need to solve for y, I would say the smallest integer that would satisfy this equation would be 4.
In case you want the answer for the question mark, putting 4 inp place of y, we get ? = 7.

Answer 5

you have to make the denominator equal, so:
4(16/y)+y(3y/4)
64/4y+3y^2/4y
(64+3y^2) / 4y

Answer 6

16/y + 3y/4

I guess you want to combine the fractions

The LCD is 4y

(4/4)(16/y) + (y/y)(3y/4)

64/(4y) + 3y^2/(4y)

(64 + 3y^2)/(4y)

Answer 7

16/y + 3y/4
= 64/4y + 3y^2/4y
=(64+3y^2)/(4y)

Answer 8

There is no way of determining what the answer to the question is without knowing what y equals. Y could be anything, therefore the answer could be anything.

Answer 9

I equals to any value you plug in for y.

Otherwise, you would have to be more clear in what you are asking for.