PLEASE HELP ME!!!!!!!
2007-10-29 04:31:46 · 4 answers · asked by mrjmiller21 1 in Science & Mathematics ➔ Physics
When the ball hits the ground, all potential energy stored will be converted to kinetic energy. Using this, we can find the velocity just as it hits the ground.
mgh = 1/2 mv^2
v = sqrt(2gh)
so momentum when the ball hits the ground = m. v
= m . sqrt(2gh)
= 0.10 * sqrt(2 * 9.8 * 12)
= 1.5336 kg m/s
2007-10-29 04:38:58 · answer #1 · answered by gauravragtah 4 · 0⤊ 0⤋
first caluclate the velocity of the ball at when it reaches the ground with V^2=2gh so 2*9.8*12=235.2
V=15.33
momentum=MV M=.10 V= 15.33 so momentum= 1.533kgm/sec
2007-10-29 04:39:12 · answer #2 · answered by kukgenius 2 · 0⤊ 0⤋
use kinematics to figure out the speed of the ball when it hits the ground
vi = 0
from vf^2 = vi^2 + 2ad
vf = sqrt(2*g*d)
the momentum of the ball is
p = m*vf
2007-10-29 04:34:46 · answer #3 · answered by civil_av8r 7 · 0⤊ 0⤋
v^2 = 2gs
v =Sq root [(2)(9.8)12]
v = 15.3 m/s
p=mv
p = (0.1kg)(15.3m/s)
p = 1.53kg m/s, downward
2007-10-29 04:42:59 · answer #4 · answered by rene c 4 · 0⤊ 0⤋