Please help answer...
3x^2+20x+17
factor completely...
2007-10-29 04:09:55 · 6 answers · asked by It's a girl due 5/11/09 4 in Science & Mathematics ➔ Mathematics
=3x^x + 20x +17
= 3x^2 +3x + 17x + 17
= 3x(x+1)+17(x+1)
=(3x+17)(x+1)
2007-10-29 04:17:08 · answer #1 · answered by MARS 3 · 1⤊ 0⤋
First multiply the first term (3) by the second term (17)
This gives you--> 51
Which two factors of 51 when added together give you 20, and when multiplied together give you 51?
17 and 3 !!!!!!!!!!!!!!
so heres the trick:
put 17 and 3 as denominators and then take the first term (3) and put it over the 17 and 3... so it'll look like this:
3/17 and 3/3 which equals 3/17 and 1/1
the numerator will represent you coefficients for your "x" and the denominator is what your gunna add
so therefore:
(3x+17)(x+1)
so x= -1, -17/3
hope that helps!
2007-10-29 11:24:54 · answer #2 · answered by carpe.diem 1 · 0⤊ 0⤋
3x^2+20x+17
=3x^2+3x+17x+17
=3x(x+1)+17(x+1)
=(x+1)(3x+17)
2007-10-29 11:25:05 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(3x + 17) * (x + 1)
2007-10-29 11:14:59 · answer #4 · answered by David Bowman 7 · 0⤊ 0⤋
(3x+17)(x+1)
Next!
2007-10-29 11:13:27 · answer #5 · answered by gebobs 6 · 0⤊ 1⤋
This is of the form
ax^+bx+c=0
a=3
b=20 c=17
x=[-b+sqrt(b^2-4ac)]/2a
x=[-b-sqrt(b^2-4ac)]/2a
x=[-20+sqt(400-204)]/6
x=[-20-sqrt(400-204)]/6
Solving
x=-1
x=-5.6666
2007-10-29 11:19:25 · answer #6 · answered by cidyah 7 · 0⤊ 1⤋