3x+4(x-8)-x=3/5(10x+15)
2007-10-28 17:33:46 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
15x + 20(x - 8) - 5x = 30x + 45
35x - 160 - 5x = 30x + 45
30x = 30x + 205
Error in question?
2007-10-28 20:43:29 · answer #1 · answered by Como 7 · 1⤊ 0⤋
Multiply out the parentheses terms. Then combine the "x" terms and the constant terms separately, and put them on opposite sides of the equation. Then divide both sides by the coefficient of x.
The first step in the process results in
6x -32 = 6x + 9
Since the x's cancel out and leave an impossible statement -32 = 9, there is no solution.
2007-10-28 20:11:31 · answer #2 · answered by Anonymous · 0⤊ 1⤋
steps:
3x + 4x - 32 - x = 6x + 9
combine like terms.
6x - 32 = 6x + 9
subtract a 6x
-32 = 0x + 9 Which equals no solution, or x = 0
Good luck.
2007-10-28 17:40:11 · answer #3 · answered by Brandon E 1 · 0⤊ 0⤋
3x+4(x-8)-x=3/5(10x+15)
6x-32=6x+9
0=41
D.N.E.
2007-10-28 17:40:43 · answer #4 · answered by info2know 3 · 0⤊ 0⤋
3x+4x-32-x=6x+9
2x+4x-6x=9+32
0=41
WTF?
Somewhat difficult to determine!hahahaha
2007-10-28 20:00:23 · answer #5 · answered by Anonymous · 0⤊ 0⤋