A container of volume V = 1.9 litres has a mass of 51.028 g when evacuated. When the container is filled with air pressure p = 3.4 atm at a temperature T = 30oC, what is the mass of the system? Treat air as an ideal gas with molar mass M = 28.25 g/mol.
Express the result in the unit [g] and to three significant figures. If you must use scientific notation, please enter as follows: e.g. 0.000123 = 1.23E-4. Please show all calculation steps so that I understand how the answer is determined
2007-10-28 15:22:57 · 2 answers · asked by Penny M 1 in Science & Mathematics ➔ Physics
PV=nRT
P- pressure
V - volume
n- number of moles
R- gas constant [0.08205784 L·atm·/(K1·mol)]
T - temperature in deg Kelvin
n=PV/RT
m(gas) =n p
m(gas) -mass of the gas
p - mass of gas in per mole
m(gas)= [(3.4 x 1.9 )/(0.082057 x (273 + 30)) ]28.25=7.3g
m(total)=m(container) +m(gas)
m(total)=51.028 + 7.3= 58.368 g
2007-10-28 15:32:12 · answer #1 · answered by Edward 7 · 0⤊ 1⤋
I didnt know that was the kind of gas you wanted to know about
2007-10-28 15:29:06 · answer #2 · answered by shightfuhk 2 · 1⤊ 0⤋