Sodium ions (Na+) moave at 0.794 m/s through a bloodstream in the arm ofa person standing near a large magnet. The magnetic force has a strength of 0.26T and makes an angle of 69 degrees with the motion of the sodium ions. The arm contains 61.3 cm3 of blood (within the magnetic field) with 1.41 x 10^20 Na+ / cm3. If no other ions are present in the arm, what would be the magnetic force on the arm? Answer in units of N.
2007-10-28 15:01:48 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
If no other ions were present in the arm, it would probably explode from the unbalanced mutual repulsion of the Na+ ions. Gack! Who writes these things?
The force on one ion is B*e0*v*sin(65), where B is the magnetic field strength, e0 is the charge on the Na+ ion (same as one electron, only positive), and v is the speed of the ion. The force on all N of them is N*B*e0*sin(65). To get N, multiply the given density times the given volume. The rest is making sure the units match up. Everything is given in MKS, so just make sure to express e0 in coulombs.
2007-10-29 16:01:09 · answer #1 · answered by husoski 7 · 0⤊ 0⤋