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Calculate the energy difference (E) for the photon absorbed when a hydrogen atom undergoes a transition from n = 1 to n = 5 for 1 mol H atoms.

2007-10-28 14:31:33 · 1 answers · asked by divastr186 2 in Science & Mathematics Chemistry

1 answers

Without considering the fine structure, the electron energy level of the hydrogen atom can be written as:
En = -2.179×10^-18 J/ n^2
Thus for n = 5:
E5 = -8.716x10^-20 J
the energy difference (E) for the photon absorbed when a hydrogen atom undergoes a transition from n = 1 to n = 5:
E5 - E1 = 2.09x10^-18 J
For 1 mol H atoms:
6.022x10^23 *(E5 - E1) = 1.26x10^6 J = 1.26 MJ

2007-10-29 14:43:21 · answer #1 · answered by Hahaha 7 · 1 0

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