can anyone factor this 64x^2-81=0?

Question

please

Answer 1

a²-b² = (a+b)(a-b)

64x² - 81 = 0
(8x)² - 9² = 0
(8x+9)(8x-9) = 0
x = {-9/8, 9/8}

Answer 2

Hi,
This is the difference of two squares, and, as you may know, there's a standard formula for that:
a²-b² = (a+b)(a-b)
Let's compare your expression with this:
64x^2-81=0
(8x)²-9² =0
So, a = 8x and b = 9. So, we can just write those twice and connect one set with a minus sign and the other with a positive sign.
(8x-9)(8x+9)=0
Of course, you can solve for the two values of x by solving each factor for x. But since you didn't ask for that, I'll not bore you with a demonstration.

FE