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5/ y - 2 + 2/ y + 2

2007-10-28 12:08:51 · 3 answers · asked by Pep C 1 in Science & Mathematics Mathematics

3 answers

Hi,

In this problem, you need to notice that the constant values of -2 and 2 would cancel out since they amount to 0 .

After cancelling these two numbers, we then see that we are left with 5/y + 2/y. In this expression, the two fractions have a common denominator of y and therefore, we are allowed to add the numerators repectively to get:

7 / y <==== FINAL ANSWER

I hope that helps you out! Please let me know if you have any other questions!

Sincerely,

Andrew

2007-10-28 12:13:24 · answer #1 · answered by The VC 06 7 · 0 0

If this is 5/(y-2) + 2 /(y+2)
then[5(y+2) + 2(y-2) ] / (y-2)(y+2)
or (7y +6) / (y^2 -4)

2007-10-28 19:15:19 · answer #2 · answered by Steve T 5 · 0 1

5/ (y - 2) + 2/ (y + 2) <-- Assumed you meant this.
= {5(y+2) + 2(y-2)}/(y^2-4)
= (5y+10+2y-4)/(y^2 -4)
= (7y+6)/(y^2-4)

2007-10-28 19:14:11 · answer #3 · answered by ironduke8159 7 · 0 1

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