Solve the following. Show Work?

Question

1. squared 5x + 10 - 15 = 0
2. squared 2x + 6 + 2 = 0
3. Find the distance between ( -3, -2) and (1,4)

Answer 1

Did you leave out the x's in the first two?

#1) 5x^2 + 10x - 15 = 0
5(x^2 + 2x - 3) = 0
(x + 3) (x - 1) = 0
x = -3 or x = 1

#2) 2x^2 + 6x + 2 = 0
2(x^2 + 3x + 1) = 0
This does not factor, but you can use the quadratic formula.

#3) d = square root {(-3-1)^2 + (-2-4)^2}
= square root {16 +36}
d = square root of 52 or 2 times square root of 13

that's it!

Answer 2

1. 5x^2 + 10x - 15 = 0 <-- Assumed you meant this
x^2-2x-3 = 0
(x-3)(x+1) = 0 --> x = 3 and x = -1

2. 2x^2 + 6X + 2 = 0 <-- Assumed you meant this
x = [-6 +/- sqrt(6^2-4*2*2) )]/4
x = [-6 +/- sqrt(20)]/4
x = -1.5 +/- .5sqrt(5)

3. Find the distance between ( -3, -2) and (1,4)
d= sqrt((4-(-2))^2 + (1 -(-3))^2)
= sqrt(36+ 16) sqrt(52) = 2sqrt(13)

Answer 3

1 -X=0

2-?

# - (5) (1)


Im pretty sure!!