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1. A block of mass m=1.20 kg is stacked on top of a block of mass M=3.20 kg and the two move together on a horizontal surface with a constant acceleration of magnitude a=4.04 m/s^2 pointing to the right under the influence of an external horizontal force of manitude F0=40.3N which is applied to mass M. The coefficient between mass m and mass M is (mu)=0.780. The coefficient of kinetic friction between block m and block M is not given. The coefficient of kinetic friction between block M and the horizontal surface is also not given.

a. What is the magnitude of the force of friction exerted by block M on m?

b. What is the magnitude of the force of friction exerted by the horizontal surface on block M?

Please show your work :)

2007-10-28 10:54:38 · 1 answers · asked by carbonatedcolor 2 in Science & Mathematics Physics

1 answers

a) Let's first see if m is slipping
F=1.2*4.04
F=4.848 N

Max friction before slipping is
1.2*9.81*0.780
=9.18 , nope not slipping, so the frictional force between m and M is 4.848 N

so
40.3-f=5.4*4.04
f=18.48 N

Note, I always used net force equals acceleration

F=m*a

j

2007-10-29 05:58:00 · answer #1 · answered by odu83 7 · 0 0

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