solve for theta where 0<theta<2pi: sin2theta=1/2?

0 ⤊

solve for theta where 0<theta<2pi: sin2theta=1/2?

2007-10-28 10:38:18 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2 answers

If sin(2*theta) = 1/2 and 0 pi/12, 5pi/12, 13pi/12, 17pi/12

2007-10-28 10:57:43 · answer #1 · answered by Demiurge42 7 · 0⤊ 0⤋

sin is Y on the unit circle
and theta can be any angle in QI and QII because in QIII and QIV the y value would be negative
so sin(theta)=1/2 where 0 theta=60 degrees and 120 degrees
theta = pi/3 and theta =2pi/3

2007-10-28 17:42:59 · answer #2 · answered by melted cheese 4 · 0⤊ 1⤋